hA (kJ/kg)
900
hB (kJ/kg)
1000
hC = hD (kJ/kg)
500
This simulation illustrates how to calculate the coefficient of performance (COP) of an ideal mechanical refrigeration system using a pressure–enthalpy diagram. Use the sliders to set the enthalpies of the refrigerant at the four principal points in the cycle. The COP value is displayed above a schematic drawing of the mechanical refrigeration system that shows where energy enters and leaves and the refrigerant’s flow direction. A plot of pressure versus enthalpy for the selected cycle is shown below the drawing. The cold side of the cycle is shown in blue and the hot side in red.
The coefficient of performance (COP) is calculated from the enthalpies of the refrigerant at the four principal points A, B, C, and D of the cycle:
COP = hA − hD hB − hA
where
COP = coefficient of performance (dimensionless)
hA = enthalpy of the refrigerant leaving the evaporator and entering the compressor (kJ/kg)
hB = enthalpy leaving the compressor and entering the condenser (kJ/kg)
hC = enthalpy leaving the condenser and entering the expansion valve (kJ/kg)
hD = enthalpy leaving the expansion valve and entering the evaporator (kJ/kg); hD = hC because expansion across the valve is isenthalpic
The numerator (hA − hD) is the heat absorbed by the refrigerant in the evaporator (the useful cooling), and the denominator (hB − hA) is the work supplied to the compressor. The pressure does not enter into the calculation and is presented on an arbitrary scale.
This simulation was created in the Department of Chemical and Biological Engineering at University of Colorado Boulder for LearnChemE.com by John L. Falconer using Claude AI. It is a JavaScript/HTML5 implementation of a Mathematica simulation by Mark D. Normand and Micha Peleg. It was prepared with financial support from the National Science Foundation (DUE 2336987 and 2336988) in collaboration with Washington State University. Address any questions or comments to LearnChemE@gmail.com.